Antud n\u00e4ites on kajastatud erinevaid viise kuidas k\u00e4sitleda viita struktuurile ning kasutada viidaaritmeetikat struktuuridest koosneva massiivi indekseerimiseks<\/p>\n
Kokku on koodis 4 erinevat n\u00e4idet kuidas tr\u00fckkida v\u00e4lja struktuuridest koosnevat massiivi. See millist kasutada v\u00f5ib s\u00f5ltuda nii eesm\u00e4rgist, kui ka enda eelistustest ja meeskonna koodin\u00f5uetest.<\/p>\n
Meeldetuletuseks – kui sul on viit struktuuridest koosnevale massiivile, siis saad kasutada ka kantsulgusid. N\u00e4iteks<\/p>\n
\/**\r\n * File: struct_pointers.c\r\n * Author: Risto Heinsar\r\n * Created: 25.02.2015\r\n * Modified: 29.05.2026\r\n *\r\n * Descriptions: A longer sample for passing structures to functions and\r\n * using pointers to access them. This code contains multiple\r\n * ways to achieve the same goal.\r\n *\/\r\n\r\n#include <stdio.h>\r\n#include <stdlib.h>\r\n\r\n#define N 20\r\n\r\ntypedef struct Employee\r\n{\r\n int employeeCode;\r\n char fName[N];\r\n char lName[N];\r\n float wage;\r\n} Employee;\r\n\r\nvoid PrintEmployee(Employee *pEmployee);\r\nvoid PrintEmployees1(Employee *pEmployees, int n);\r\nvoid PrintEmployees2(Employee *pEmployees, int n);\r\nvoid PrintEmployees3(Employee *pEmployees, int n);\r\nvoid PrintEmployees4(Employee *pEmployees, int n);\r\n\r\nint main(void)\r\n{\r\n Employee manager = {75, \"Indrek\", \"Tamm\", 12.75f};\r\n Employee staff[] = {{20, \"Toomas\", \"Vali\", 5.22f},\r\n {23, \"Madis\", \"Mets\", 4.21f},\r\n {25, \"Kaspar\", \"Kuusk\", 3.25f}};\r\n \r\n \/\/ Calculate number of employees in the array\r\n int n = sizeof(staff) \/ sizeof(Employee);\r\n\r\n \/\/ Prints a single employee records\r\n PrintEmployee(&manager);\r\n putchar('\\n');\r\n \r\n \/\/ Three different ways of printing employee data\r\n PrintEmployees1(staff, n);\r\n PrintEmployees2(staff, n);\r\n PrintEmployees3(staff, n);\r\n PrintEmployees4(staff, n);\r\n\r\n return EXIT_SUCCESS;\r\n}\r\n\r\n\r\n\/**\r\n * Description: Prints the records of a single employee\r\n * \r\n * Parameters: pEmployee - pointer to single employee data\r\n * \r\n * Return: -\r\n *\/\r\nvoid PrintEmployee(Employee *pEmployee)\r\n{\r\n printf(\"Employee %06d, %s %s makes %2.2f in an hour\\n\", \r\n pEmployee->employeeCode, \r\n pEmployee->fName, \r\n pEmployee->lName,\r\n pEmployee->wage);\r\n}\r\n\r\n\r\n\/**\r\n * Description: This is an example print function that prints all employee data\r\n * using pointer arithmetic to index the struct array. Prinding is\r\n * done directly.\r\n * \r\n * Parameters: pEmployees - pointer to employee data\r\n * n - number of employees\r\n * \r\n * Return: -\r\n *\/\r\nvoid PrintEmployees1(Employee *pEmployees, int n)\r\n{\r\n for (int i = 0; i < n; i++)\r\n {\r\n printf(\"Employee %06d, %s %s makes %2.2f in an hour\\n\", \r\n (pEmployees + i)->employeeCode, \r\n (pEmployees + i)->fName,\r\n (pEmployees + i)->lName, \r\n (pEmployees + i)->wage);\r\n }\r\n putchar('\\n'); \r\n}\r\n\r\n\r\n\/**\r\n * Description: This is very similar to PrintEmployees1(), but in this case \r\n * we are incrementing the the copy of the pointer address.\r\n * \r\n * Parameters: pEmployees - pointer to employee data\r\n * n - number of employees\r\n * \r\n * Return: -\r\n *\/\r\nvoid PrintEmployees2(Employee *pEmployees, int n)\r\n{\r\n \/\/ Store pointer to the first member separately (for clarity)\r\n Employee *pEmployee = pEmployees;\r\n \r\n for (int i = 0; i < n; i++)\r\n {\r\n \/* Print the current employee *\/\r\n printf(\"Employee %06d, %s %s makes %2.2f in an hour\\n\", \r\n pEmployee->employeeCode, \r\n pEmployee->fName,\r\n pEmployee->lName, \r\n pEmployee->wage);\r\n \r\n \/* Move the employee pointer to the next struct member (employee) *\/\r\n pEmployee++;\r\n }\r\n putchar('\\n');\r\n}\r\n\r\n\r\n\/**\r\n * Description: This is very similar to PrintEmployees1(), but in this case \r\n * we are using an exisitng print function to handle printing.\r\n * Useuful if you need to print the same data in multiple places.\r\n * \r\n * Parameters: pEmployees - pointer to employee data\r\n * n - number of employees\r\n * \r\n * Return: -\r\n *\/\r\nvoid PrintEmployees3(Employee *pEmployees, int n)\r\n{\r\n \/\/ Store pointer to the first member separately (for clarity)\r\n Employee *pEmployee = pEmployees;\r\n \r\n for (int i = 0; i < n; i++)\r\n {\r\n \/* Print the current employee *\/\r\n PrintEmployee(pEmployee);\r\n \r\n \/* Move the employee pointer to the next struct member (employee) *\/\r\n pEmployee++;\r\n }\r\n putchar('\\n');\r\n}\r\n\r\n\/**\r\n * Description: This is again the in same notion as the previous examples,\r\n * but this time we make a dedicated pointer to an employee\r\n * struct in the loop, offering even cleaner code\r\n * \r\n * Parameters: pEmployees - pointer to employee data\r\n * n - number of employees\r\n * \r\n * Return: -\r\n *\/\r\nvoid PrintEmployees4(Employee *pEmployees, int n)\r\n{\r\n for (int i = 0; i < n; i++)\r\n {\r\n \/* Select the employee from the struct pointer array *\/\r\n Employee *pEmployee = pEmployees + i;\r\n \r\n \/* Print the current employee *\/\r\n PrintEmployee(pEmployee);\r\n }\r\n putchar('\\n');\r\n}\r\n<\/pre>\n <\/p>\n","protected":false},"excerpt":{"rendered":"
Antud n\u00e4ites on kajastatud erinevaid viise kuidas k\u00e4sitleda viita struktuurile ning kasutada viidaaritmeetikat struktuuridest koosneva massiivi indekseerimiseks Kokku on koodis 4 erinevat n\u00e4idet kuidas tr\u00fckkida v\u00e4lja struktuuridest koosnevat massiivi. See millist kasutada v\u00f5ib s\u00f5ltuda nii eesm\u00e4rgist, kui ka enda eelistustest ja meeskonna koodin\u00f5uetest. Meeldetuletuseks – kui sul on viit struktuuridest koosnevale massiivile, siis saad kasutada … Loe edasi Struktuuriviida n\u00e4ited<\/span>